The outer wheel track of a center pivot traces a circle with a radius of 1000 feet. What is the circumference of this circle in feet?

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Multiple Choice

The outer wheel track of a center pivot traces a circle with a radius of 1000 feet. What is the circumference of this circle in feet?

Explanation:
The distance around a circle, its circumference, is found with C = 2πr. With a radius of 1000 feet, multiply 2 by π and by 1000: C = 2π × 1000 = 2000π feet. Using π ≈ 3.1416 gives C ≈ 2000 × 3.1416 = 6,283.2 feet. So the wheel track travels about 6,283.2 feet around the circle. A common mistake is using πr instead of 2πr, which would yield about 3,141.6 feet and is too small because it would only account for half the circle.

The distance around a circle, its circumference, is found with C = 2πr. With a radius of 1000 feet, multiply 2 by π and by 1000: C = 2π × 1000 = 2000π feet. Using π ≈ 3.1416 gives C ≈ 2000 × 3.1416 = 6,283.2 feet. So the wheel track travels about 6,283.2 feet around the circle. A common mistake is using πr instead of 2πr, which would yield about 3,141.6 feet and is too small because it would only account for half the circle.

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